Question

What is the equation of the line with a slope of -4 that passes through the point (5, -1)?

Options:
A) y = -4x + 21
B) y = -4x - 21
C) y = 4x + 21
D) y = 4x - 21

Answer 1

The equation of the line with a slope of -4 that passes through the point (5, -1) is y = -4x + 19.

Step-by-step explanation:

To find the equation of a line with a given slope and a point, we can use the point-slope form, which is:

y - y1 = m(x - x1)

Where (x1, y1) is the given point and m is the slope. In this case, the slope is -4 and the point is (5, -1).

Plugging these values into the point-slope form, we get:

y - (-1) = -4(x - 5)

Simplifying the equation, we get:

y + 1 = -4x + 20

Finally, subtracting 1 from both sides, we get the equation in slope-intercept form:

y = -4x + 19