Question

Quation of a line passing through (5, -6) parallel to: E 12 (d) 7x - 12y = 5 (f) 2y = 5

Answer 1

Input data

A = (5, -6)

`7x-12y=5`

Procedure

First we must determine the slope of the straight line to make it parallel

`y=(7)/(12)x-(5)/(12)`

The slope of the straight line would be m = 7/12

`\begin{gathered} b=y-mx \\ b=-6-(7)/(12)\cdot5 \\ b=-6-(35)/(12) \\ b=-(72)/(12)-(35)/(12) \\ b=-(107)/(12) \end{gathered}`

The equation of the line that passes through the point (5,-6) with a slope of 7/12 is

`y=(7)/(12)x-(107)/(12)`