Final answer:
The average power output of a weightlifter lifting 276 kg to a height of 1.81 m in 0.81 s is approximately 6050.22 W, which is closest to option B) 6050.56 W.
Step-by-step explanation:
The question asks us to calculate the average power output of a weightlifter who lifts a weight to a certain height within a given time frame. Power is defined as the rate at which work is done or energy is transferred. It can be calculated with the formula Power (P) = Work (W) / Time (t), where work done is given by the product of the force (in this case, the weight lifted) and the displacement (height to which the weight is lifted).
First, we need to calculate the work done by the weightlifter. The force in this case is equal to the weight of the object, which is mass (m) × acceleration due to gravity (g), and the displacement is the height (h) the object is lifted to.
Work (W) = m × g × h
Where,
- m = 276 kg
- g = 9.8 m/s² (standard acceleration due to gravity)
- h = 1.81 m
Calculating the work done:
W = 276 kg × 9.8 m/s² × 1.81 m = 4900.68 J
Now, we divide the work done by the time taken to determine the average power output:
Power (P) = 4900.68 J / 0.81 s = 6050.22 W
Therefore, the average power output of the weightlifter is approximately 6050.22 W, which matches option B) 6050.56 W, considering minimal rounding differences.