Final Answer:
K + U = 1/2 * mv² + 9.8 * mh
Step-by-step explanation:
The total energy (K + U) of the falling object is the sum of its kinetic energy (K) and potential energy (U). The expressions for kinetic and potential energy are given by:
K = 1/2 * mv²
U = 9.8 * mh
Substituting these into the total energy expression:
K + U = 1/2 * mv² + 9.8 * mh
This expression represents the total mechanical energy of the object at any given time during its fall. The term 1/2 * mv² is the kinetic energy, which depends on the velocity of the object, and 9.8 * mh is the potential energy, which depends on the height of the object and the acceleration due to gravity (9.8 m/s²).
The sum K + U is constant throughout the fall, as no external forces (like air resistance) are considered. This is a result of the conservation of mechanical energy, stating that the total mechanical energy of a system remains constant if only conservative forces (like gravity) are at play. As the object falls, it converts potential energy into kinetic energy and vice versa, but the total remains constant.
During the fall, the object gains kinetic energy as it accelerates downward and loses potential energy as it descends. This is reflected in the equation K + U, where the gain in kinetic energy is accompanied by a proportional loss in potential energy.