Final Answer:
D) 7877.025 J work is done when a sled 3.5-kg and a rider of 50-kg are pulled across the snow a distance of 15-m.
Step-by-step explanation:
The work done (W) can be calculated using the formula:
![\[ W = \text{Force} * \text{Distance} * \cos(\theta) \]](https://img.qammunity.org/2024/formulas/physics/high-school/eizmfwwum34jjy1pe3sdyb72ao205htw69.png)
Where:
- Force is the applied force,
- Distance is the distance over which the force is applied,
-
is the angle between the force and the direction of motion.
In this case, the force is the gravitational force acting on the sled and the rider, and it's given by the weight
where
is the mass and
is the acceleration due to gravity (approximately
The angle
is not given, but we assume the force is applied horizontally, so
Now, substitute the values into the formula:
![\[ W = (m_{\text{sled}} + m_{\text{rider}}) * g * d \]](https://img.qammunity.org/2024/formulas/physics/high-school/x722ng4al1qpmy5rwedl2gttstp41bolib.png)
![\[ W = (3.5 \, \text{kg} + 50 \, \text{kg}) * 9.8 \, \text{m/s}^2 * 15 \, \text{m} \]](https://img.qammunity.org/2024/formulas/physics/high-school/spg3h8wh47gtdm88vhd12v4os4v4b52azx.png)
![\[ W = 53.5 \, \text{kg} * 9.8 \, \text{m/s}^2 * 15 \, \text{m} \]](https://img.qammunity.org/2024/formulas/physics/high-school/jb43tva1ljhzsoxb68gcukdmh0h1abnl17.png)
![\[ W = 7877.025 \, \text{J} \]](https://img.qammunity.org/2024/formulas/physics/high-school/uxhxvl636gfx1ytsr8ux9y4abghxa69pu7.png)
Therefore, the correct answer is D) 7877.025 J.