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A car goes from 6.2 m/s to 12.9 m/s in 5 seconds. Calculate (a) the acceleration and (b) the distance covered by the car in that time.

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Final answer:

The car's acceleration is 1.34 m/s², and the distance it covers in 5 seconds is 47.75 meters

Step-by-step explanation:

To calculate the acceleration (a) of the car, we can use the formula for acceleration which is the change in velocity (Δv) divided by the time (t) over which the change occurred:

a = Δv / t

Here, the initial velocity (u) is 6.2 m/s and the final velocity (v) is 12.9 m/s, and the time is 5 seconds. So,

a = (12.9 m/s - 6.2 m/s) / 5 s

a = 6.7 m/s² / 5 s = 1.34 m/s²

Next, to calculate the distance covered (d), we can use the formula derived from the kinematic equations:

d = ut + 0.5at²

Where u is the initial velocity, a is the acceleration, and t is the time. Thus:

d = (6.2 m/s * 5 s) + 0.5 * 1.34 m/s² * (5 s)²

d = 31 m + 0.5 * 1.34 m/s² * 25 s²

d = 31 m + 16.75 m = 47.75 m

The car's acceleration is 1.34 m/s², and the distance covered in that time is 47.75 meters.

User Dmitry Stolbov
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