Question

Bob has 8 more dimes than quarters. If he has a total of $4.30, how many of each coin does he have?

A) 10 dimes and 2 quarters.
B) 14 dimes and 6 quarters.
C) 5 dimes and 13 quarters.
D) 18 dimes and 10 quarters.

Answer 1

Bob has 10 quarters and 18 dimes.

Step-by-step explanation:

Let's use algebra to solve this problem.

Let's say Bob has x quarters. Since he has 8 more dimes than quarters, he has x+8 dimes.

The value of the quarters is 25x cents and the value of the dimes is 10(x+8) cents.

The total value of the coins is $4.30 or 430 cents.

We can set up the following equation: 25x + 10(x+8) = 430

Simplifying the equation, we get: 25x + 10x + 80 = 430

Combining like terms, we get: 35x + 80 = 430

Subtracting 80 from both sides, we get: 35x = 350

Dividing both sides by 35, we get: x = 10

So, Bob has 10 quarters and 10+8=18 dimes.

Therefore, the correct answer is option D) 18 dimes and 10 quarters.