Final answer:
The balanced equation for the reaction between HBr and KOH is HBr(aq) + KOH(aq) -> H₂O(l) + KBr(aq). This acid-base neutralization reaction follows the stoichiometry of one mole of each reactant producing one mole of water and one mole of potassium bromide, confirming that the equation is balanced.
Step-by-step explanation:
The balanced chemical equation for the reaction between HBr (hydrobromic acid) and KOH (potassium hydroxide) is represented by option (a):
HBr(aq) + KOH(aq) → H₂O(l) + KBr(aq)
In this acid-base neutralization reaction, one mole of HBr reacts with one mole of KOH to produce one mole of water (H₂O) and one mole of potassium bromide (KBr). By counting the number of atoms of each element, we confirm that the equation is balanced: there is one hydrogen atom on the reactant side (from HBr) and one on the product side (from H₂O); one bromine atom on each side; one potassium atom on each side; and one oxygen atom on each side.
\