108k views
2 votes
Kevin is drawing building. He is using a scale

factor of 2in : 10 ft. The drawing is 8 inches
tall. How tall is the building in real life?
What is something that will need to reduce to
see? What is something that will enlarged to
see?

User ZeroFruit
by
8.5k points

1 Answer

3 votes

Final answer:

Using a scale factor of 2in:10ft, an 8-inch tall drawing represents a 40-foot tall building in real life. Reduction examples include maps, while enlargement examples could be microscopic organisms.

Step-by-step explanation:

Kevin is drawing a building using a scale factor of 2 inches to 10 feet. To find how tall the building is in real life, we set up a proportion using the given scale factor. First, we write the unit scale as a ratio, which in this case is 1 inch equals 5 feet (since 2 inches equals 10 feet).

Next, we compare the scale height to the actual height using the ratio. The drawing is 8 inches tall, so our proportion will be:

  • 1 inch / 5 feet = 8 inches / x feet

After setting up the proportion, we cross multiply to solve for 'x', which represents the actual height of the building.

1 inch * x feet = 8 inches * 5 feet.
x feet = 8 inches * 5 feet / 1 inch.
x feet = 40 feet.

Therefore, the actual height of the building is 40 feet.

To visualize things that need to be reduced to see, one might imagine details on a map or a complex machine being scaled down. Conversely, for things that are enlarged to see, consider items like bacteria under a microscope, where enlargement is necessary to study their structure.

User KingKongFrog
by
8.0k points