Question

If 4a^445 – 40²73 = 360, a – b = 1, a² + 62

= 13, and 4a²b = 72, what is the
value of ab?

Answer 1

The value of ab cannot be found as the value of a is not real.

Step-by-step explanation:

In this case, we have a system of equations:

a - b = 1

a² + 62 = 13

4a²b = 72

From the second equation, we can solve for a:

a² = 13 - 62

a² = -49

a = ± √(-49)

Since we can't take the square root of a negative number, the value of a is not real.

Therefore, we cannot find the value of ab.