Final answer:
The heat energy produced when raising the temperature of 500 grams of water by 7 degrees Celsius is calculated using the specific heat capacity of water. It amounts to 14,630 Joules.
Step-by-step explanation:
Calculating the Heat Energy Produced
The question asks about the heat energy produced when the temperature of a given mass of water is increased. To answer this question, we need to consider the specific heat capacity of water, which is the amount of heat energy required to raise the temperature of 1 gram of water by 1 degree Celsius.
The specific heat capacity of water is approximately 4.18 Joules per gram per degree Celsius (J/g/°C). To find the total heat energy produced, we use the formula:
Heat energy (Q) = mass (m) * specific heat capacity (c) * change in temperature (ΔT)
Given that the mass of the water (m) is 500 grams and the temperature change (ΔT) is 7 degrees Celsius, we can calculate the heat energy as follows:
Q = 500 g * 4.18 J/g/°C * 7 °C
Q = 500 g * 29.26 J/°C
Q = 14,630 Joules
Therefore, when the temperature of 500 grams of water is raised by 7 degrees Celsius, the heat energy produced is 14,630 Joules.