Question

How many moles of hydrogen gas can be produced if 0.57 moles of hydrochloric acid, HC1, reacts with excess solid zinc according to the following chemical equation?

2 HC1 + Zn → H2 + ZnCl2

Answer 1

From 0.57 moles of hydrochloric acid reacting with excess zinc, 0.285 moles of hydrogen gas will be produced according to the stoichiometry of the balanced reaction equation.

Step-by-step explanation:

The question asks how many moles of hydrogen gas can be produced from 0.57 moles of hydrochloric acid (HCl) when reacting with excess solid zinc according to the chemical equation 2 HCl + Zn → H2 + ZnCl2. To solve this, we use the stoichiometry of the balanced equation which shows that two moles of HCl produce one mole of H2.

Since we start with 0.57 moles of HCl, we can determine the amount of H2 produced using the mole ratio from the balanced chemical equation:

• 0.57 moles HCl × (1 mole H2 / 2 moles HCl) = 0.285 moles H2

Therefore, 0.285 moles of hydrogen gas will be produced from 0.57 moles of hydrochloric acid reacting with excess zinc.

Answer 2

0.57 moles of hydrochloric acid reacting with excess zinc according to the equation 2 HC1 + Zn → H2 + ZnCl2 will produce 0.285 moles of hydrogen gas.

Step-by-step explanation:

The student's question pertains to stoichiometry, a concept in chemistry that involves the calculation of products and reactants in chemical reactions. According to the balanced chemical equation 2 HC1 + Zn → H2 + ZnCl2, 2 moles of hydrochloric acid (HCl) produce 1 mole of hydrogen gas (H2). Given that the student has 0.57 moles of HCl, we can calculate the moles of hydrogen gas formed using the ratio from the balanced equation.

First we write the ratio:

• 2 moles HCl : 1 mole H2

Thus, for 0.57 moles of HCl, we perform the following calculation:

(0.57 moles HCl) × (1 mole H2) / (2 moles HCl) = 0.285 moles H2

Therefore, if 0.57 moles of hydrochloric acid reacts with excess solid zinc, 0.285 moles of hydrogen gas can be produced.