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Which system of inequalities has no solution?

A. y < 2x - 4
y > 2x + 1

B. 2x + y ≥ 3
y^2 - 2x - 3

C. 4x + 4y < 16
x > y + 16

D. y < -6x - 24
y < 6x + 6"

User Lflores
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1 Answer

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Final answer:

The system of inequalities with no solution is A. y < 2x - 4 and y > 2x + 1.

Step-by-step explanation:

To determine which system of inequalities has no solution, we need to analyze each option and identify any inconsistencies or contradictions.

A. The system of inequalities y < 2x - 4 and y > 2x + 1 can be graphed as two parallel lines with different slopes. Since these lines will never intersect, this system has no solution.

B. The system of inequalities 2x + y ≥ 3 and y^2 - 2x - 3 can also be graphed. However, the graph of y^2 - 2x - 3 is a quadratic curve, while the graph of 2x + y ≥ 3 is a line. These two graphs will not intersect, so this system has no solution as well.

C. The system of inequalities 4x + 4y < 16 and x > y + 16 can be graphed as two lines. These lines will intersect, meaning there is a solution for this system.

D. The system of inequalities y < -6x - 24 and y < 6x + 6 also has lines that are parallel. Since these lines will never intersect, this system has no solution as well.

Therefore, the correct answer is option A: y < 2x - 4 and y > 2x + 1.

User Clauswey
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