185k views
4 votes
Which system of inequalities has no solution?

A. y < 2x - 4
y > 2x + 1

B. 2x + y ≥ 3
y^2 - 2x - 3

C. 4x + 4y < 16
x > y + 16

D. y < -6x - 24
y < 6x + 6"

User Lflores
by
7.6k points

1 Answer

2 votes

Final answer:

The system of inequalities with no solution is A. y < 2x - 4 and y > 2x + 1.

Step-by-step explanation:

To determine which system of inequalities has no solution, we need to analyze each option and identify any inconsistencies or contradictions.

A. The system of inequalities y < 2x - 4 and y > 2x + 1 can be graphed as two parallel lines with different slopes. Since these lines will never intersect, this system has no solution.

B. The system of inequalities 2x + y ≥ 3 and y^2 - 2x - 3 can also be graphed. However, the graph of y^2 - 2x - 3 is a quadratic curve, while the graph of 2x + y ≥ 3 is a line. These two graphs will not intersect, so this system has no solution as well.

C. The system of inequalities 4x + 4y < 16 and x > y + 16 can be graphed as two lines. These lines will intersect, meaning there is a solution for this system.

D. The system of inequalities y < -6x - 24 and y < 6x + 6 also has lines that are parallel. Since these lines will never intersect, this system has no solution as well.

Therefore, the correct answer is option A: y < 2x - 4 and y > 2x + 1.

User Clauswey
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories