Final answer:
By using Planck's constant and the frequency given, the energy of the photon is calculated as 4.51 x 10^-18 J, with the closest provided option being 4.27 x 10^-18 J.
Step-by-step explanation:
To convert 6.8x10^15 1/s into joules for the photon, we use the formula E = hf, where E is the energy, h is Planck's constant (6.626 x 10^-34 J s), and f is the frequency. Given the frequency of 6.8x10^15 1/s, we get:
E = (6.626 x 10^-34 J s)(6.8x10^15 1/s) = 4.50568 x 10^-18 J
When rounded to three significant figures, this gives us 4.51 x 10^-18 J, which is not an exact match to any of the options given. However, the closest option to our calculated value would be (a) 4.27 x 10^-18 J.