Question

A ball is thrown into the air with an initial upward velocity of 48 ft/s. Its height h in feet after t seconds is given by the function h(t) = -16t² + 48t + 4.

i.) What height will the ball be when 2 seconds have passed?
a) 64 feet
b) 84 feet
c) 108 feet
d) 112 feet

Answer 1

After plugging the value of 2 seconds into the height function, the ball's height is calculated to be 36 feet, which does not match any of the multiple-choice options given.

Step-by-step explanation:

To determine what height the ball will be at after 2 seconds using the function h(t) = -16t² + 48t + 4, we simply plug in the value for t and solve:

h(2) = -16(2)² + 48(2) + 4

h(2) = -16(4) + 96 + 4

h(2) = -64 + 96 + 4

h(2) = 36 feet

If we look at the multiple-choice options provided to the student, none of them match the correct answer of 36 feet. Therefore, the correct height is not listed among the options.