Question

An ice cube (25 g) is at -38.0°C. How much energy is required to bring it to 0°C?

Heat capacity (c) for solid water is 2.10 J/g°C, Hf= 334 J/g
A) 1,045 J
B) 1,352.5 J
C) 671 J
D) 1,670 J

Answer 1

To bring the ice cube from -38.0°C to 0°C, the total energy required is 1,045 J.

Step-by-step explanation:

To find the amount of energy required to bring an ice cube from -38.0°C to 0°C, we need to consider two steps: heating the ice cube from -38.0°C to 0°C and melting the ice cube.

First, we calculate the energy required to heat the ice cube using the equation Q = m * c * ΔT, where Q is the energy, m is the mass of the ice cube (25 g), c is the heat capacity of solid water (2.10 J/g°C), and ΔT is the change in temperature (0°C - (-38.0°C) = 38.0°C).

Q₁ = 25 g * 2.10 J/g°C * 38.0°C = 1995 J.

Next, we calculate the energy required to melt the ice using the equation Q = m * Hf, where Q is the energy, m is the mass of the ice cube (25 g), and Hf is the heat of fusion (334 J/g).

Q₂ = 25 g * 334 J/g = 8350 J.

The total energy required is the sum of Q₁ and Q₂.

Total energy = 1995 J + 8350 J = 10345 J.

Therefore, the correct answer is A) 1,045 J.