Final answer:
To find an equation of a line that is parallel to the given line and passes through point P(-3, -14), we need to use the fact that parallel lines have the same slope. The equation of the line that is parallel to the given line and contains point P(-3, -14) is y = 6x - 11.
Step-by-step explanation:
To find an equation of a line that is parallel to the given line and passes through point P(-3, -14), we need to use the fact that parallel lines have the same slope. The given line has a slope of 6, so the parallel line will also have a slope of 6. Using the point-slope form of a line, y - y1 = m(x - x1), we can substitute the values m = 6, x1 = -3, and y1 = -14, to obtain the equation: y - (-14) = 6(x - (-3)). Simplifying this equation gives: y = 6x - 11. Therefore, Option 2: y = 6x - 11 is the equation of the line that is parallel to the given line and contains point P(-3, -14).