Final answer:
The area of triangle XZP is found to be 55 in², which is half the area of the parallelogram XZRP since the diagonals of a parallelogram bisect each other creating two congruent triangles.
Step-by-step explanation:
The question pertains to finding the area of triangle XZP given the area of parallelogram XZRP. In a parallelogram, opposite sides are equal in length, and diagonals bisect each other, thus dividing the parallelogram into two congruent triangles. Therefore, the area of triangle XZP is equal to half the area of parallelogram XZRP.
We are given that the area of the parallelogram XZRP is 110 in2 and the height is 10 in. We can express this relationship as:
Area of parallelogram = base × height
Since the base of the parallelogram can be calculated by dividing the area of the parallelogram by the height (n), we find the base by 110 in2 / 10 in = 11 in.
Now, using the formula for the area of a triangle which is (1/2 × base × height), we can calculate the area of triangle XZP:
Area of triangle XZP = 1/2 × 11 in × 10 in = 55 in2