Given,
The mass of the train, m=1.5×10 kg=15 kg
The force with which the locomotive pulls the train, F=7.5×10⁵ N
The initial speed of the train, u=0 m/s
The final speed of the train, v=85 km/hr
The final speed in m/s is
From Newton's second law,
Where a is the acceleration of the train.
On substituting the known values,
From the equation of motion,
Where t is the time interval in which the train will accelerate to the given speed.
On substituting the known values,
Thus the train will accelerate to the given speed in 4.72×10⁻⁴ s