Final answer:
The speed of the rocket at the end of 8 seconds is 28.8 m/s. The rocket travels a distance of 28.8 meters during both the first four seconds and the last four seconds of the 8-second trip.
Step-by-step explanation:
(A) To find the speed of the rocket at the end of 8 seconds, we can use the equation:
v = vo + at
Where:
v is the final velocity,
vo is the initial velocity (0 m/s as the rocket starts from rest),
a is the acceleration (3.6 m/s²),
t is the time (8 seconds).
Substituting the values, we have:
v = 0 + 3.6 * 8 = 28.8 m/s
(B) To determine the distance traveled during the first four seconds, we can use the equation:
d = vo * t + 0.5 * a * t^2
Where:
d is the distance,
t is the time (4 seconds),
Substituting the values, we have:
d = 0 * 4 + 0.5 * 3.6 * 4^2 = 28.8 m
(C) To calculate the distance traveled during the last four seconds, we can use the same equation:
d = vo * t + 0.5 * a * t^2
Substituting the values:
d = 0 * 4 + 0.5 * 3.6 * 4^2 = 28.8 m