Question

Which of the following represents the balanced double displacement reaction between Sodium Chloride (NaCl) and Copper Sulfate (CuSO₄)?

A) NaCl + CuSO₄ --> NaSO₄ + CuCl
B) NaCl + Cu(SO₄) --> Cl(SO₄) + NaCu
C) NaCl + CuSO₄ --> Na₂SO₄ + CuCl₂
D) 2NaCl + CuSO₄ --> Na₂SO₄ + CuCl₂

Answer 1

The balanced double displacement reaction between Sodium Chloride and Copper Sulfate is 2NaCl + CuSO4 --> Na2SO4 + CuCl2.Answer is option (d).

Step-by-step explanation:

The correct option for the balanced double displacement reaction between Sodium Chloride (NaCl) and Copper Sulfate (CuSO4) is D) 2NaCl + CuSO4 --> Na2SO4 + CuCl2.

In this reaction, the sodium (Na+) ions pair with sulfate (SO42-) ions to form sodium sulfate (Na2SO4), and the copper (Cu2+) ions pair with chloride (Cl-) ions to form copper(II) chloride (CuCl2). Since the sodium and sulfate ions are spectator ions and remain in the aqueous solution, the actual change is the precipitate formation of copper(II) chloride.