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A fishbowl shaped like a sphere is filled with water. The fishbowl has a diameter of 18 inches. What is the volume of the fishbowl in cubic inches, rounded to the nearest tenth?

User Raghuvd
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1 Answer

3 votes

Final answer:

The volume of the spherical fishbowl with a diameter of 18 inches is approximately 3,052.1 cubic inches, calculated using the formula V = (4/3)πr^3.

Step-by-step explanation:

The volume of a spherical fishbowl can be calculated using the formula for the volume of a sphere, which is V = (4/3)πr^3. With the diameter of the fishbowl given as 18 inches, the radius is half of that, which is 9 inches. Substituting the radius into the formula, we get:

V = (4/3)π(9 inches)^3

Now, doing the calculation:

V = (4/3)π(729 cubic inches)

V = 4π(243 cubic inches)

V ≈ 3,052.1 cubic inches

Therefore, the volume of the fishbowl is approximately 3,052.1 cubic inches.

User Sorifiend
by
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