63.5k views
2 votes
Find the equation of the straight line passing through the point E(9, -2) and is perpendicular to the line y = -3/2x + 5/2.

A) y = 3/2x - 29/2
B) y = 2/3x + 16/3
C) y = 2/3x - 29/3
D) y = 3/2x + 29/2

1 Answer

3 votes

Final answer:

The equation of the straight line passing through point E(9, -2) and perpendicular to y = -3/2x + 5/2 is y = 2/3x - 8.

Step-by-step explanation:

To find the equation of the line that is perpendicular to a given line, we need to determine the slope of the given line and then find the negative reciprocal of that slope. The slope of the given line is -3/2, so the slope of the line perpendicular to it will be 2/3. Since the line passes through the point (9, -2), we can use the point-slope form of a linear equation to find the equation of the line:

y - y1 = m(x - x1)

Substituting the values, we get:

y - (-2) = 2/3(x - 9)

y + 2 = 2/3x - 6

y = 2/3x - 6 - 2

y = 2/3x - 8

Therefore, the equation of the straight line passing through point E(9, -2) and perpendicular to the line y = -3/2x + 5/2 is y = 2/3x - 8.

User Riley Bracken
by
8.4k points