Question

A diver leaps into the air from a platform 5 meters above the water's surface. The diver's initial speed is 4.4 m/s and her launch angle is 70 degrees. How long is the diver in the air? How far from the end of the board does she hit the water?

A) Time in the air: 1.92 seconds, Distance from the end of the board: 4.92 meters
B) Time in the air: 2.34 seconds, Distance from the end of the board: 5.12 meters
C) Time in the air: 2.18 seconds, Distance from the end of the board: 4.64 meters
D) Time in the air: 1.75 seconds, Distance from the end of the board: 4.15 meters

Answer 1

The diver is in the air for 1.92 seconds and hits the water 4.92 meters from the end of the board.

Step-by-step explanation:

To solve this problem, we can use the equations of motion for projectile motion. The time in the air can be found using the equation:

time = (2 * initial speed * sine(launch angle)) / acceleration

Plugging in the values given in the question, we get:

time = (2 * 4.4 * sin(70)) / 9.8 = 1.92 seconds

The distance from the end of the board can be found using the equation:

distance = initial speed * cosine(launch angle) * time

Plugging in the values given in the question, we get:

distance = 4.4 * cos(70) * 1.92 = 4.92 meters