Final answer:
The heat required to increase the temperature of 350 g of water from 20°C to 56°C is calculated using the specific heat formula and is approximately 52912.8 J.
Step-by-step explanation:
To calculate the amount of heat in joules needed to increase the temperature of 350 g of water from 20°C to 56°C, we use the following formula where q is the heat transferred, m is the mass, C is the specific heat capacity, and ΔT is the change in temperature:
q = m × C × ΔT
Given the mass m = 350 g, specific heat C = 4.184 J/g°C (the specific heat of water), and the temperature change ΔT = 56°C - 20°C = 36°C, the calculation is as follows:
q = 350 g × 4.184 J/g°C × 36°C
q = 52912.8 J
Therefore, the amount of heat required is approximately 52912.8 J, which is closest to the given option (b) 53,445 J. However, the exact calculated value should be considered as the correct answer.