Question

A pendulum swings on the surface of the Earth. It has a length of 1.60 meters. What is the period of this pendulum in seconds?

A) 0.51 s
B) 1.02 s
C) 2.54 s
D) 1.26 s

Answer 1

To find the period of a pendulum with a length of 1.60 meters, use the formula T = 2π√(L/g). After plugging in the values for length and the acceleration due to gravity, we find that the closest period to the calculated value is 2.54 seconds.

Step-by-step explanation:

The period of a pendulum is determined by its length and the acceleration due to gravity using the formula:

T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity (approximately 9.81 m/s² on Earth).

For a pendulum with a length of 1.60 meters, the period can be calculated as follows:

T = 2π√(1.60/9.81)

T ≈ 2π√(0.163)

T ≈ 2π√(0.403)

T ≈ 2π(0.635)

T ≈ 2(3.1416)(0.635)

T ≈ 6.2832(0.635)

T ≈ 3.99 s

Therefore, the closest answer to the calculated period is:

C) 2.54 s