Final answer:
To determine the volume of a 0.100 M K2Cr2O7 solution that contains 73.5 g of K2Cr2O7, we calculate the moles of K2Cr2O7 and then divide by the molarity, giving us a volume of 2.5 liters or 2500 mL.
Step-by-step explanation:
A student asked what volume of a 0.100 M K2Cr2O7 solution contains 73.5 g of K2Cr2O7. To find the answer, we first need to calculate the number of moles of potassium dichromate in 73.5 g.
The molar mass of K2Cr2O7 is approximately 294.18 g/mol. Using the formula:
Number of moles = mass (g) / molar mass (g/mol),
we get:
Number of moles of K2Cr2O7 = 73.5 g / 294.18 g/mol ≈ 0.25 mol.
Since the solution's molarity (M) is the number of moles of solute per liter of solution, we can use the formula:
Molarity (M) = moles of solute / volume of solution in liters,
to find the volume:
Volume of solution = moles of solute / molarity (M) = 0.25 mol / 0.100 M = 2.5 L or 2500 mL.