Question

The density of pure gold is 19.32 g/cm³ at 20°C. If 25.75 g of pure gold nuggets is added to a graduated cylinder containing 13.3 mL of water, to what volume level will the water in the cylinder rise? (Use the given density as the conversion factor to calculate the wanted measurement).

Answer 1

To determine the new volume level in the graduated cylinder, the volume of gold occupied by 25.75 g of gold is calculated using its density and then added to the initial water volume of 13.3 mL.

Step-by-step explanation:

The student is asking about the volume displacement caused by the addition of a certain mass of gold to water measured in a graduated cylinder, which is a problem that involves the density formula. To find the new volume level in the graduated cylinder, we can use the mass of the gold and its density to calculate the volume that the gold occupies. Given the density of gold, 19.32 g/cm³ at 20°C, we would first calculate the volume of gold by using the formula for density, which is density (d) = mass (m) / volume (V). Rearranging this formula gives us volume (V) = mass (m) / density (d). With a mass of 25.75 g of gold, we can then use this formula to calculate the volume it will occupy and add it to the initial water volume of 13.3 mL to find the new water level.