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A gas is heated from 263K to 308K. The volume is increased from 24.0L to 35.0L. If the original pressure was 1.00 atm, what is the new pressure?

Option 1: 1.08 atm
Option 2: 0.80 atm
Option 3: 0.78 atm
Option 4: 0.59 atm

1 Answer

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Final answer:

To find the new pressure, we can use the combined gas law formula: P1V1/T1 = P2V2/T2 Given: P1 = 1.00 atm, V1 = 24.0 L, T1 = 263 K, V2 = 35.0 L, T2 = 308 K Substituting the values into the formula, The new pressure of the gas is approximately 0.80 atm.

Step-by-step explanation:

To find the new pressure, we can use the combined gas law formula: P1V1/T1 = P2V2/T2 Given: P1 = 1.00 atm, V1 = 24.0 L, T1 = 263 K, V2 = 35.0 L, T2 = 308 K Substituting the values into the formula, we have: (1.00 atm)(24.0 L)/(263 K) = P2(35.0 L)/(308 K) Solving for P2, we get P2 ≈ 0.80 atm (Option 2).

the new pressure, we can use the combined gas law formula: P1V1/T1 = P2V2/T2 Given: P1 = 1.00 atm, V1 = 24.0 L, T1 = 263 K, V2 = 35.0 L, T2 = 308 K Substituting the values into the formula, The new pressure of the gas is approximately 0.80 atm.

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