Question

A car traveling at 11 m/s slows to a stop over 5 seconds. Determine how far the car travels during this time.

a. 10.5 m
b. 158 m
c. 4.2 m
d. 27.5 m

Answer 1

The car travels a distance of 27.5 m during the 5-second time interval while slowing to a stop.

Step-by-step explanation:

To determine the distance the car travels during the 5-second time interval while slowing to a stop, we can use the formula:

distance = (initial velocity + final velocity) * time / 2

Given that the initial velocity is 11 m/s, the final velocity is 0 m/s, and the time is 5 seconds, we can substitute these values into the formula:

distance = (11 + 0) * 5 / 2 = 55 / 2 = 27.5 m

Therefore, the car travels a distance of 27.5 m during this time.