Question

An object moves from position x=-1.88m to x=4.27m. What is its displacement?

A) 2.39 meters
B) 6.15 meters
C) -6.15 meters
D) -2.39 meters

Answer 1

The displacement of an object moving from x=-1.88m to x=4.27m is calculated by subtracting the initial position from the final position, resulting in a positive displacement of 6.15 meters.

Step-by-step explanation:

An object that moves from position x=-1.88m to x=4.27m has a displacement calculated by the formula Δx = xf - x0. Displacement is the change in position and is a vector quantity, which means it has both magnitude and direction. To find the displacement, subtract the initial position (x0) from the final position (xf):

Δx = xf - x0 = 4.27m - (-1.88m) = 4.27m + 1.88m = 6.15 meters.

Therefore, the correct answer is B) 6.15 meters. This value is positive because the motion is to the right, which is typically considered the positive direction in a one-dimensional coordinate system.