Question

The mean score on a calculus exam was 40, and the standard deviation was 5. The teacher decided to double everyone's score, and then added 7 points. What are the values of the mean and standard deviation of the distribution of transformed exam scores?

A) Mean = 87, Standard Deviation = 10
B) Mean = 40, Standard Deviation = 5
C) Mean = 80, Standard Deviation = 7
D) Mean = 47, Standard Deviation = 12

Answer 1

The values of the mean and standard deviation of the distribution of transformed exam scores are Mean = 87 and Standard Deviation = 5.

Step-by-step explanation:

To find the values of the mean and standard deviation of the distribution of transformed exam scores, we need to apply the given transformations to the original mean and standard deviation.

To double everyone's score, we multiply the original mean by 2. So, the new mean is 40 * 2 = 80.

To add 7 points to everyone's score, we add 7 to the new mean. So, the new mean is 80 + 7 = 87.

The new standard deviation remains the same as the original standard deviation, which is 5.

Therefore, the values of the mean and standard deviation of the distribution of transformed exam scores are:

Mean = 87

Standard Deviation = 5