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A businessman accidentally drops his mobile while standing on a balcony. If you don't count the effect of air resistance, its speed after two seconds is ____ m/s.

a) 0
b) 9.8
c) 19.6
d) 20

User Yots
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Final answer:

The mobile's speed after two seconds of free fall, ignoring air resistance, is calculated using the formula V = at, yielding a speed of 19.6 m/s.

Step-by-step explanation:

When the businessman drops his mobile without considering air resistance, the mobile will accelerate downwards due to gravity. On Earth, the acceleration due to gravity g is approximately 9.8 m/s². The speed of the mobile after two seconds can be calculated using the formula V = at, where V is the final velocity, a is the acceleration due to gravity, and t is the time in seconds. Plugging in the values, we get V = 9.8 m/s² × 2 s = 19.6 m/s. Therefore, the speed of the mobile after two seconds is 19.6 m/s.

User Mensah
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