Final answer:
The electron geometry of C3H8O is A) tetrahedral, as each carbon atom in the molecule has four regions of electron density that are arranged to minimize repulsion, in accordance with VSEPR theory.
Step-by-step explanation:
The electron geometry of C3H8O, which is a molecule of propanol, can be determined by evaluating the regions of electron density around the carbon atoms. Each carbon atom in C3H8O has four regions of electron density, which typically include single bonds to hydrogen atoms or other carbon atoms and potentially a single bond to an oxygen atom.
These regions of electron density are arranged in a tetrahedral geometry for each carbon atom, which minimizes the repulsion between electron pairs according to the VSEPR theory. Therefore, the options provided, the correct electron geometry for C3H8O is tetrahedral.