Final answer:
1.00 milligram of CuSO4 contains approximately 398 micrograms of copper, based on the atomic masses of copper and the components of copper sulfate, CuSO4.
Step-by-step explanation:
To determine how many micrograms of copper are in 1.00 milligram of CuSO4, we need to know the percent composition of copper in the compound. Copper sulfate, CuSO4, consists of one copper atom, one sulfur atom, and four oxygen atoms. By using the atomic masses of these elements (approximately copper: 63.5, sulfur: 32.1, and oxygen: 16), we can calculate the molar mass of CuSO4.
The molar mass is calculated as follows: (1 × 63.5) + (1 × 32.1) + (4 × 16) ≈ 159.6 grams/mole. The mass of copper in one mole of CuSO4 is the atomic mass of copper, which is 63.5 grams. To find the percentage of copper in CuSO4 we use the ratio 63.5 g Cu / 159.6 g CuSO4 and multiply by 100, yielding approximately 39.85%.
Therefore, 1.00 milligram (which is 1000 micrograms) of CuSO4 contains 39.85% copper. To find the number of micrograms of copper, multiply 1000 micrograms by 0.3985 (or 39.85%). This equals to ≈ 398 micrograms of copper.