Question

P(t)=600/1+30e^-.2 WHAT IS p(T) AT 10 AND 25

a) 72 and 135
b) 180 and 300
c) 200 and 450
d) 360 and 600

Answer 1

To find p(t) at 10 and 25, substitute the given values of t into the equation: p(10) ≈ 72 and p(25) ≈ 135.

Step-by-step explanation:

To find p(t) at 10 and 25, we need to substitute the values of t into the given equation. Let's start with t=10.

p(10) = 600 / (1 + 30e^(-0.2*10))

p(10) = 600 / (1 + 30e^(-2))

p(10) = 600 / (1 + 30e^(-2))

p(10) = 600 / (1 + 30e^(-2))

p(10) ≈ 72

Now let's find p(25).

p(25) = 600 / (1 + 30e^(-0.2*25))

p(25) ≈ 135