Final answer:
The temperature of the aluminum after it loses 2.83 x 10^3 J would be 1.57 °C less than its initial temperature.
Step-by-step explanation:
To find the temperature of the aluminum after it loses 2.83 x 10^3 J, we need to calculate the change in temperature of the aluminum.
We can use the equation Q = mcΔT, where Q is the amount of heat energy transferred, m is the mass of the aluminum, c is the specific heat of aluminum, and ΔT is the change in temperature.
Given that the specific heat of aluminum is 900 J/kg-°C, we can rearrange the equation to solve for ΔT: ΔT = Q / (mc). Substituting the values, we get ΔT = (2.83 x 10^3 J) / (2 kg x 900 J/kg-°C) = 1.57 °C.
Therefore, the temperature of the aluminum after it loses 2.83 x 10^3 J would be 1.57 °C less than its initial temperature.