Question

A basketball court has width of 44 less than the length. If the perimeter is 288 feet, what were the dimensions of the court?

(Work must be shown)

Answer 1

The length of the basketball court is 94 feet and the width is 50 feet.

Step-by-step explanation:

Let's assume the length of the basketball court is x.

1. The width of the basketball court is x - 44 feet.
2. The perimeter of a rectangle is given by the formula P = 2(length + width). So, in this case, we have 2(x + (x - 44)) = 288.
3. Simplifying the equation, we get 2(2x - 44) = 288.
4. Distributing and combining like terms, we have 4x - 88 = 288.
5. Adding 88 to both sides of the equation, we get 4x = 376.
6. Dividing both sides of the equation by 4, we find that x = 94.

Therefore, the length of the basketball court is 94 feet, and the width is 94 - 44 = 50 feet.