Final answer:
To raise the temperature of the air from 30° C to 180° C in an industrial chamber, the electric heater consumes 180 million joules (or 180 megajoules) of electrical energy, given the mass of the air is 1,200 kg and the specific heat of air is 1,000 J/kg°C.
Step-by-step explanation:
To calculate the amount of electrical energy the heater consumes to raise the temperature of the air in the industrial chamber from 30° C to 180° C, we can use the formula:
E = m ⋅ c ⋅ ΔT
Where:
- E is the energy in joules (J)
- m is the mass of air in kilograms (kg)
- c is the specific heat capacity in J/kg°C
- ΔT is the change in temperature in degrees Celsius (°C)
Given:
- m = 1,200 kg
- c = 1,000 J/kg°C
- ΔT = (180 - 30) = 150°C
We get:
E = 1,200 kg ⋅ 1,000 J/kg°C ⋅ 150°C = 180,000,000 J
So the heater consumes 180 million joules (or 180 megajoules) of electrical energy.