Question

"Rocky the Squirrel leaps off of a tree branch with an initial horizontal velocity of 3.4 m/s. He reaches a second branch that is 2.8 meters below where it began.

a. How much time does Rocky’s flight take?
b. What is the final vertical velocity of Rocky at the second branch?
c. What is the horizontal displacement of Rocky?"

Answer 1

To find the time of flight, use t = (2 * h) / g. To find the final vertical velocity, use v = u + (g * t). To find the horizontal displacement, use d = v * t.

Step-by-step explanation:

To solve this problem, we can break it down into different parts:

a. To find the time of flight, we can use the equation:

t = (2 * h) / g

where t is the time of flight, h is the vertical displacement, and g is the acceleration due to gravity. In this case, h is 2.8 meters, so:

t = (2 * 2.8) / 9.8 = 0.57 seconds

b. To find the final vertical velocity, we can use the equation:

v = u + (g * t)

where v is the final vertical velocity, u is the initial vertical velocity (which is 0 in this case since Rocky is leaping horizontally), g is the acceleration due to gravity, and t is the time of flight. So:

v = 0 + (9.8 * 0.57) = 5.586 m/s

c. To find the horizontal displacement, we can use the equation:

d = v * t

where d is the horizontal displacement, v is the horizontal velocity, and t is the time of flight. In this case, v is 3.4 m/s and t is 0.57 seconds, so:

d = 3.4 * 0.57 = 1.938 meters