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A 2000kg car traveling at 27m/s slows to a halt in 9 seconds by letting the wind resistance stop the car. How much was the wind resistance?

User Kahsn
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Final answer:

The wind resistance that halted a 2000kg car traveling at 27m/s in 9 seconds is calculated as -6000 N, which means the force is in the opposite direction to the car's movement.

Step-by-step explanation:

To calculate the wind resistance that brought a 2000kg car to a halt from 27m/s in 9 seconds, we can use Newton's second law of motion, which states that force equals mass times acceleration (F = ma). First, we need to find the acceleration of the car, which can be done using the formula for acceleration (a = Δv/Δt), where Δv is the change in velocity and Δt is the change in time. Since the car comes to a halt, the final velocity is 0 m/s, and the initial velocity is 27 m/s, and the time taken to stop is 9 seconds.

The change in velocity (Δv) is 27 m/s (since the car is coming to a stop, it is 27 m/s - 0 m/s). The change in time (Δt) is 9 seconds. Thus, the acceleration (a) is -27 m/s² / 9 s = -3 m/s². The negative sign indicates that the car is decelerating. We now use the mass of the car (m = 2000 kg) to find the force of wind resistance (F = m * a) which is 2000 kg * (-3 m/s²) = -6000 N. The negative sign indicates that the force of wind resistance is in the opposite direction of the car's initial motion.

User Brad Barber
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