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The formula to calculate the distance an object has free fallen is

d=1/2gt^2
where
d represents the distance the object has fallen in meters,
g represents the force of gravity (9.8 m/s²), and
t represents how long the object was falling in seconds. If a thrown object takes 15 seconds to land, how high off the ground was the object when it was thrown? Round your answer to the nearest tenth and do NOT include units.

A) 110.3

B) 110.4

C) 110.5

D) 110.6

User John Day
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1 Answer

2 votes

Final answer:

To calculate the height off the ground when the object was thrown, we can use the formula d = 1/2gt^2. Plugging in the given values, we find that the object was approximately 110.3 meters high off the ground.

Step-by-step explanation:

To calculate the height off the ground when the object was thrown, we can rearrange the formula d = 1/2gt^2 to solve for d. In this case, g = 9.8 m/s² and t = 15 s. Plugging these values into the formula, we get:

d = 1/2 * 9.8 * 15^2

d = 1/2 * 9.8 * 225

d = 1/2 * 2205

d = 2205 / 2

d = 1102.5

Rounding to the nearest tenth, the object was approximately 110.3 meters high off the ground when it was thrown. Therefore, the correct answer is A) 110.3.

User Serjas
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