Final answer:
To calculate the height off the ground when the object was thrown, we can use the formula d = 1/2gt^2. Plugging in the given values, we find that the object was approximately 110.3 meters high off the ground.
Step-by-step explanation:
To calculate the height off the ground when the object was thrown, we can rearrange the formula d = 1/2gt^2 to solve for d. In this case, g = 9.8 m/s² and t = 15 s. Plugging these values into the formula, we get:
d = 1/2 * 9.8 * 15^2
d = 1/2 * 9.8 * 225
d = 1/2 * 2205
d = 2205 / 2
d = 1102.5
Rounding to the nearest tenth, the object was approximately 110.3 meters high off the ground when it was thrown. Therefore, the correct answer is A) 110.3.