Question

"2. Calculate the atomic mass for the following FAKE elements given the information provided for its isotopes.

a. Octoberine

Isotope 1:

Mass (amu): 89.58
Percent Abundance: 44.87%
Isotope 2:
Mass (amu): 93.11
Percent Abundance: 55.13%
What is the atomic mass of "Octoberine"?

A) 88.25 amu
B) 90.37 amu
C) 91.57 amu
D) 94.46 amu

Answer 1

atomic mass is approximately 91.49 amu. To calculate the atomic mass of an element, you need to multiply the mass of each isotope by its percent abundance and then sum up the results. For Octoberine, with two isotopes and given percent abundances and masses.

Step-by-step explanation:

To calculate the atomic mass of an element, you need to multiply the mass of each isotope by its percent abundance and then sum up the results. For the element Octoberine, we have two isotopes:

Isotope 1: Mass (amu): 89.58, Percent Abundance: 44.87%

Isotope 2: Mass (amu): 93.11, Percent Abundance: 55.13%

Using the formula for atomic mass:

Atomic mass = (percent abundance1 * mass1) + (percent abundance2 * mass2)

Substituting the values:

Atomic mass = (0.4487 * 89.58) + (0.5513 * 93.11)

Calculating:

Atomic mass ≈ 89.58 * 0.4487 + 93.11 * 0.5513 ≈ 40.18 + 51.31 ≈ 91.49 amu

So, the atomic mass of Octoberine is approximately 91.49 amu.