Final answer:
The distance moved by an object with an initial velocity of 225 m/s, undergoing an acceleration of 62 m/s² for 26 seconds, is 26812 meters, which suggests that there may be an error in the question or options as this answer is not listed among the choices.
Step-by-step explanation:
To calculate the distance moved by an object experiencing an acceleration, we can use the formula for motion under constant acceleration:
s = ut + (½)at2
where:
- s is the displacement
- u is the initial velocity
- a is the acceleration.
- t is the time
Given that the initial velocity (u) is 225 m/s, the acceleration (a) is 62 m/s2, and time (t) is 26 seconds, we can calculate the displacement as follows:
s = (225 m/s)(26 s) + (½)(62 m/s2)(26 s)2
s = 5850 m + (½)(62)(676)
s = 5850 m + 20962 m
s = 26812 m
Therefore, the distance moved by the object is 26812 meters, which is not listed in the given options, implying a potential error in the question or options provided.