Final answer:
To find the zeros of the quadratic function h(x) = x^2 - 16x - 80, we can use the quadratic formula. The solutions for x are -4 and 20.
Step-by-step explanation:
To find the zeros of the quadratic function h(x) = x^2 - 16x - 80, we set the function equal to zero and solve for x. Rearranging the equation, we have x^2 - 16x - 80 = 0. We can then use the quadratic formula to find the values of x.
The quadratic formula is x = (-b ± √(b^2 - 4ac)) / (2a), where a, b, and c are the coefficients of the quadratic equation. In this case, a = 1, b = -16, and c = -80.
Substituting the values into the formula, we get x = (16 ± √(16^2 - 4(1)(-80))) / (2(1)). Simplifying further, we have x = (16 ± √(256 + 320)) / 2, which gives us x = (16 ± √576) / 2. The square root of 576 is 24, so x = (16 ± 24) / 2. Evaluating both possibilities, we find that the zeros of the function are x = -4 and x = 20.