Question

Determine the final velocity of a skateboarder if they start from rest and accelerate at a rate of 75 m/s^2 forward for 3 seconds.

A. 225 m/s
B. 50 m/s
C. 225 m/s^2
D. 50 m/s^2

Answer 1

Using the kinematic equation v = u + at, and substituting the given acceleration of 75 m/s² and time of 3 seconds, the final velocity of the skateboarder is found to be 225 m/s. The correct answer is A. 225 m/s.

Step-by-step explanation:

To determine the final velocity of a skateboarder who starts from rest and accelerates at a constant rate, we can use the basic kinematic equation for constant acceleration, which is v = u + at, where:

• v is the final velocity,
• u is the initial velocity (which is 0 m/s since the skateboarder starts from rest),
• a is the acceleration, and
• t is the time over which the acceleration occurs.

Plugging in the values given in the question (a = 75 m/s

2

and t = 3 s), we get

v = 0 m/s + (75 m/s

2

× 3 s)

. This calculates to a final velocity

v

of 225 m/s.

Therefore, the correct answer is A. 225 m/s.