(x^5+9x^4+8x^3-25x^2+19x+17)÷(x+3)

Rhavin asked Dec 8, 2023

330,526 views

31 votes

Rhavin asked Dec 8, 2023

2.9k points

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

16 votes

we have the following:

$\left(x^5+9x^4+8x^3-25x^2+19x+17\right)/\left(x+3\right)$

| 1 9 8 -25 19 17

-3 | -3 -18 30 -15 -12

------------------------------------------

| 1 6 -10 5 4 5

therefore:

$x^4+6x^3-10x^2+5x+4,\text{ Rest: 5}$

Amol Raje answered Dec 14, 2023

2.9k points

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers