(x^5+9x^4+8x^3-25x^2+19x+17)÷(x+3)

Rhavin asked Dec 8, 2023

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Rhavin asked Dec 8, 2023

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16 votes

we have the following:

$\left(x^5+9x^4+8x^3-25x^2+19x+17\right)/\left(x+3\right)$

| 1 9 8 -25 19 17

-3 | -3 -18 30 -15 -12

------------------------------------------

| 1 6 -10 5 4 5

therefore:

$x^4+6x^3-10x^2+5x+4,\text{ Rest: 5}$

Amol Raje answered Dec 14, 2023

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