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Write an equation in slope-intercept form that passes through the point (3, 9) and has a slope of -5

User Jjchiw
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Final answer:

To write the equation of a line in slope-intercept form that passes through the point (3, 9) with a slope of -5, use the equation y = mx + b. Plug in the slope and point to get y = -5x + 24 as the final equation.

Step-by-step explanation:

The student's question is about writing an equation in slope-intercept form. To write the equation of a line that passes through the point (3, 9) and has a slope of -5, we can use the slope-intercept form of a line, which is y = mx + b, where m is the slope and b is the y-intercept. Since we know the slope (m = -5) and a point on the line (3, 9), we can substitute these values into the slope-intercept form to find the y-intercept:

y - 9 = -5(x - 3).

Simplifying this equation, we get:

y - 9 = -5x + 15

Adding 9 to both sides:

y = -5x + 24.

Therefore, the equation of the line in slope-intercept form is y = -5x + 24.

User Borisano
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