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On a coordinate plane, a line goes through points (negative 2, 4) and (0, negative 4).

Linear functions are expressed by the graph and equation. Select all that apply.

OPTION 1: The slope is positive for both functions.
OPTION 2: The equation has a steeper slope than the line in the graph.
OPTION 3: The y-intercept is the same for both.
OPTION 4: The graph and the equation express an equivalent function.

User Firemaples
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1 Answer

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Final answer:

The slope of the given line is negative as it goes through (-2, 4) and (0, -4), thus refuting OPTION 1. With different y-intercepts and no exact equation to compare to, OPTION 3 and OPTION 4 are incorrect, and OPTION 2 cannot be assessed without more information. Therefore, none of the options apply to the given line.

Step-by-step explanation:

In attempting to understand the characteristics of a linear function based on a graph or an equation, there are specific elements that you need to consider. Given the line that goes through points (-2, 4) and (0, -4), the slope of the line can be determined by the rise over run method, which calculates to (-4 - 4)/ (0 + 2) = -8/2 = -4. Therefore, the slope is negative, which means that OPTION 1 stating that the slope is positive is incorrect.

For OPTION 2, without the specific equation of the other function, this cannot be accurately assessed. However, if the line graph specified in FIGURE A1 with a slope of 3 and y-intercept of 9 were to be compared to the line through (-2, 4) and (0, -4), then the slopes would be different, and thus the slope of the equation could not be steeper or less steep without additional information.

As for the y-intercept, since the provided line goes through (0, -4), the y-intercept for this line is -4. The y-intercept in FIGURE A1 is 9. Therefore, OPTION 3 claiming that the y-intercept is the same for both is incorrect since the y-intercepts are -4 and 9, respectively.

Finally, since the slopes and y-intercepts between the line graph in FIGURE A1 and the provided line are different, OPTION 4 stating that both express an equivalent function is incorrect.

User Raskal
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